Call forward to mutiple numbers?
ccchih:
RonR,
By applying the rule {12341234567:ph,sp2(12347654321)}
If the call is from 12341234567, the PHONE Port rings and the call is forked to 12347654321 using SP2 as expected.
You are right. It's working as expected this way.
Let's just swapping the order of ph and sp2 to {sp2(12347654321),12341234567:ph} and make a call from 12341234567.
Amazingly, only the PHONE Port rings this time.
RonR:
Quote from: ccchih on January 06, 2012, 01:06:48 am
Let's just swapping the order of ph and sp2 to {sp2(12347654321),12341234567:ph} and make a call from 12341234567.
Amazingly, only the PHONE Port rings this time.
Confirmed.
And if the call is not from 12341234567, the call is totally ignored and NOT forked to sp2(12347654321) as expected.
RonR:
ccchih,
Apparently there can be only one caller-list per rule, not one per terminal, and a caller-list is associated with the whole rule and not a particular terminal. As a result, a caller-list, if present, must be the first thing in a rule, to the left of a colon and prior to any terminals. If the caller-list is false, none of the terminals in the rule are used. I think it makes much more sense the way you and I assumed it worked, but...
Now, what is the actual scenario you're trying to accomplish?
ccchih:
RonR,
Thank you very much for your help! I am trying to make the following settings done.
1. make terminalA rings first and ring terminalB simultaneously 4 secs later
2. ring terminalA only for callerA and ring all the terminals for other callers
Any suggestions?
RonR:
Quote from: ccchih on January 06, 2012, 07:52:37 pm
1. make terminalA rings first and ring terminalB simultaneously 4 secs later
2. ring terminalA only for callerA and ring all the terminals for other callers
{12341234567:sp1(12341111111},{sp1(12341111111),sp2(12342222222;d=4)}
Calls from 12341234567 will ring 12341111111 using SP1.
Calls from all others with ring 12341111111 using SP1 and 12342222222 using SP2, with the SP2 call being delayed 4 seconds.
Does that fit the bill?
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